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2023-05-29 RealBridge Primrose Hill

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2023-05-29 RealBridge Primrose Hill:
Iain Cross - Lindsey Jacobs 6th 51.6%


N
S		Board 1
420
37.5%
 KQ1092
J9
J6
K1073
10
7 7
16
Charles Rudgard
Colleen Harvey
  
65
A74
K109852
94		 43
865
Q7
AJ8652
4= by N Lead Q
par:420.4 (N)
 NT
N  7  61010  6
S  7  61010  6
E  5  7  3  2  3
W  5  7  3  2  3
Double Dummy Solv:Bo Haglund
 
  AJ87
KQ1032
A43
Q		 
N
S		Board 2
150
50%
 1043
A984
864
AKQ
13
10 5
12
Charles Rudgard
Colleen Harvey
  
A72
KQJ103
1097
104		 K965
762
Q52
863
3+2 by S Lead K
par:630.3NT+1 (N)
 NT
N1110  7  810
S1110  7  810
E  2  2  5  5  3
W  2  2  5  4  3
Double Dummy Solv:Bo Haglund
 
  QJ8
5
AKJ3
J9752		 

N
S		Board 3
200
75%
 J108532
K92
QJ
Q7
9
4 13
14
Jo Jarrold
Mary Winner
  
4
QJ10853
43
J1042		 Q6
A6
AK8765
953
3+2 by N Lead A
par:430.3NT+1 (N)
 NT
N  8  6  5  910
S  8  6  5  9  9
E  5  6  8  3  3
W  5  6  8  3  3
Double Dummy Solv:Bo Haglund
 
  AK97
74
1092
AK86		 
N
S		Board 4
100
75%
AJ975
654
108752
5
14 6
15
Jo Jarrold
Mary Winner
  
AQ7432
8
AQJ32
J		 J95
K432
98
Q643
4-1 by W Lead 8
par:140.3 (N)
 NT
N  8  5  9  4  5
S  9  5  9  4  6
E  4  8  4  8  5
W  4  8  4  8  5
Double Dummy Solv:Bo Haglund
 
  K1086
Q106
K107
AK9		 

N
S		Board 5
120
50%
 97
96
Q10874
A1063
6
5 11
18
Caroline Medawar
Maureen Betts
  
J64
K74
96
J8742		 AQ83
J1085
J32
K9
2NT= by N Lead 3
par:600.3NT (N)
 NT
N  810  8  7  9
S  710  8  7  9
E  5  3  5  5  4
W  5  3  5  5  4
Double Dummy Solv:Bo Haglund
 
  K1052
AQ32
AK5
Q5		 
N
S		Board 6
-150
0%
 J9864
854
A82
A4
9
13 8
10
Caroline Medawar
Maureen Betts
  
AK7
K9732
1076
K3		 Q105
AQ
954
108765
1NT+2 by W Lead 6
par:-110.2 (E)
 NT
N  5  7  5  6  5
S  5  7  5  6  5
E  7  5  8  6  6
W  7  5  8  6  6
Double Dummy Solv:Bo Haglund
 
  32
J106
KQJ3
QJ92		 

E
W		Board 7
100
25%
 KJ72
J104
Q9
9653
7
11 12
10
Anthony Morris
Sally Mackenzie
  
A8
K82
A8762
1082		 Q6543
A65
J10
KQ4
2NT-1 by E Lead 3
par:-90.1NT (E)
 NT
N  6  5  7  5  6
S  6  5  7  5  6
E  6  8  6  7  7
W  6  8  6  7  7
Double Dummy Solv:Bo Haglund
 
  109
Q973
K543
AJ7		 
E
W		Board 8
-400
75%
 K
1093
QJ10763
J96
7
18 10
5
Anthony Morris
Sally Mackenzie
  
AJ654
K2
AK8
K73		 872
A87
954
AQ105
3NT= by W Lead Q
par:-450.4+1 (E)
 NT
N  1  4  5  2  2
S  1  4  5  2  2
E11  9  81110
W11  9  81110
Double Dummy Solv:Bo Haglund
 
  Q1093
QJ654
2
842		 

N
S		Board 9
400
87.5%
 KQJ102
10543
8
Q76
8
3 11
18
Bob Starr
Lionel Ziman
  
9753
J876
J73
J9		 64
K9
KQ9642
K85
3NT= by S Lead 3
par:980.6 (N)
 NT
N12  7111210
S12  7111210
E  1  6  2  1  1
W  1  6  2  1  1
Double Dummy Solv:Bo Haglund
 
  A8
AQ2
A105
A10432		 
N
S		Board 10
-110
0%
 Q53
J10
A10653
K94
10
8 11
11
Bob Starr
Lionel Ziman
  
J4
62
QJ4
A108532		 A10976
A9873
K98
2= by E Lead 7
par:-110.1+1 (E)
 NT
N  6  7  5  5  6
S  6  6  5  5  5
E  6  6  8  7  6
W  6  6  8  7  6
Double Dummy Solv:Bo Haglund
 
  K82
KQ54
72
QJ76		 

N
S		Board 11
180
100%
 Q9743
9
QJ95
853
5
5 13
17
Jan Wiener
Jane Simpson
  
652
842
K
Q109642		 A10
AJ76
1087432
A
2NT+2 by S Lead K
par:430.3NT+1 (N)
 NT
N  6  8  7  810
S  6  8  7  810
E  6  5  5  3  3
W  6  5  4  3  3
Double Dummy Solv:Bo Haglund
 
  KJ8
KQ1053
A6
KJ7		 
N
S		Board 12
110
37.5%
 AKJ
J652
76
9763
9
8 10
13
Jan Wiener
Jane Simpson
  
875
KQ94
QJ104
102		 Q64
A103
98532
A4
2+1 by S Lead Q
par:140.3 (N)
 NT
N  9  5  6  9  8
S  9  5  6  9  8
E  4  8  7  4  5
W  4  8  7  4  5
Double Dummy Solv:Bo Haglund
 
  10932
87
AK
KQJ85		 

E
W		Board 13
-100
50%
 AK95
K9
A1075
1092
14
10 4
12
cindy
Sally Stopford
  
Q6
J1062
KJ86
K83		 J432
43
932
QJ54
3NT-1 by N Lead 4
par:600.3NT (N)
 NT
N  8  9  9  9  9
S  8  9  9  9  9
E  5  4  3  3  4
W  5  4  3  3  4
Double Dummy Solv:Bo Haglund
 
  1087
AQ875
Q4
A76		 
E
W		Board 14
400
37.5%
 AK4
Q64
J843
K95
13
6 8
13
cindy
Sally Stopford
  
9632
A1075
97
Q73		 87
J82
AQ1052
J104
3NT= by S Lead 2
par:140.1+2 (N)
 NT
N  9  7  8  9  8
S  9  7  8  9  8
E  4  6  5  4  5
W  4  6  5  4  5
Double Dummy Solv:Bo Haglund
 
  QJ105
K93
K6
A862		 

E
W		Board 15
-420
100%
 1043
A62
K54
K742
10
11 13
6
Pippa Warrell
Sophie Jolowicz
  
A65
QJ
A9873
863		 QJ982
K103

AQJ95
4= by E Lead 4
par:-450.4+1 (E)
 NT
N  2  6  6  2  2
S  1  5  6  1  1
E11  7  71110
W11  7  71110
Double Dummy Solv:Bo Haglund
 
  K7
98754
QJ1062
10		 
E
W		Board 16
200
25%
 K97642
AKQ
A73
10
16
13 4
7
Pippa Warrell
Sophie Jolowicz
  
AQJ10
643
K10
QJ72
J107
QJ8654
8653
1NTX-1 by W Lead 4
par:140.1+2 (N)
 NT
N  6  7  8  9  8
S  6  6  8  9  8
E  7  6  5  4  5
W  7  6  5  4  5
Double Dummy Solv:Bo Haglund
 
  853
9852
92
AK94